Respuesta :

Answer: 121.5 in³

Explanation:

[tex]\textnormal{Volume }= \cfrac{4}{3} \pi (4.5)^3 = 121.5 \pi \ in^3[/tex]
r = d/2 = 9/2 = 4.5
volume of sphere = 4/3*π (r) ^3

= 4/3π(4.5)^3

= 121.5π in^3