Respuesta :
The height is 52 feet.
Using t=3, we have:
-3² + 15(3) + 16 = -9 + 45 + 16 = 52
Using t=3, we have:
-3² + 15(3) + 16 = -9 + 45 + 16 = 52
we are given
[tex] h(t)=-t^2+15t+16 [/tex]
where h(t) is height in feet
t is time in seconds
now, we can plug t=3 and find height
[tex] h(3)=-(3)^2+15(3)+16 [/tex]
[tex] h(3)=-9+45+16 [/tex]
[tex] h(3)=52 [/tex]
so,
the height of the model rocket after 3 seconds from launch is 52 feet.......Answer
