An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of r(t) = 85e−0.04t liters per minute. How much oil leaks out during the first hour? (Round your answer to the nearest liter.)
Given the rate of water flow is given by: r(t)=85e^(-0.04t) thus the amount of water flow in the first hour when t=1, will be: r(1)=85e^(-0.04*1) =81.667 thus the amount of water that flowed out will be: 85-81.667 =3.333 liters
