Solving the expression by completing square method we shall have: x^2-4x+14=13 this can be written: x^2-4x=13-14 x^2-4x=-1 but c=(b/2a)^2 c=(-4/2*1)^2=4 thus we shall have: x^2-4x+4=-1+4 factoring the LHS we get: (x-2)(x-2)=3 (x-2)^2=3 getting the square root of both sides: x-2=+/-√3 hence x=2+/-√3 Thus the equivalent equation will be: x^2-4x+4=3
