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Let x be normally distributed with mean μ = 133 and standard deviation σ = 23. use table 1.
a. find p(x ≤ 100). (round "z" value to 2 decimal places and final answer to 4 decimal places.) p(x ≤ 100)
b. find p(95 ≤ x ≤ 110). (round "z" value to 2 decimal places and final answer to 4 decimal places.) p(95 ≤ x ≤ 110)
c. find x such that p(x ≤ x) = 0.350. (round "z" value and final answer to 2 decimal places.) x
d. find x such that p(x > x) = 0.920. (round "z" value and final answer to 2 decimal places.)

Respuesta :

a) z value =  (x - π) / σ   = 100 - 133 /  23  =  -1.43
p(<= 100) = 0.0764

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