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Find the equation of the line that has these features: slope, m=-6/5 passes through the point (-5,10)

Respuesta :

we know that

the equation of the line is 
y-y1=m(x-x1)
then
m=-6/5 passes through the point (-5,10)
y-10=(-6/5)*(x+5)-------> y-10=(-6x/5)-6------------> y=
(-6x/5)+4---------> y=-1.2x+4

see the attached figure

the answer is
y=-1.2x+4

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