Respuesta :

a. [tex] \frac{1.25 mol}{1} * \frac{22.4 L}{1 mol} =28.1 L[/tex]
b. [tex] \frac{0.335 mol C2H6}{1} * \frac{22.4 L}{1 mol} =7.50 L C2H6[/tex]

22.4 L = 1 mol at STP