Respuesta :

AREA OF A REGULAR PENTAGON EQUATION:

A = 1/4 √5(5+2√5) a² ;  a = side

A = 1/4 * √5(5+2√5) * 8²
A = 1/4 * √5(5+2(2.24) * 64
A = 1/4 * √5(5+4.48) * 64
A = 1/4 * √5(9.48 * 64
A = 1/4 * √47.4 * 64
A = 1/4 * 6.88 * 64
A = 1/4 * 440.32
A = 110.08 cm²