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26-01-2018
Mathematics

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What is the value of x? Round to the nearest tenth if necessary

What is the value of x Round to the nearest tenth if necessary class=

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26-01-2018

Hello!!

We can use the Pythagorean Theorem (a^2 + b^2 = c^2) to solve for x.

6^2 + 15^2 = x^2
36 + 225 = x^2
x^2 = 261
x = sqrt(261) = 3 sqrt(29)

Hope this helps!! Let me know if you have ANY questions.

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