uhaxteams uhaxteams

26-01-2018
Mathematics

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please help and explain how to do this. thank you in advance!

Use natural logarithms to solve the equation. Round to the nearest thousandth. 3e^2x +5=27

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Аноним Аноним

26-01-2018

We want to solve
[tex]3e^{2x}+5=27[/tex]

Subtract 5 from each side.
[tex]3e^{2x}=22[/tex]
Divide each side by 3.
[tex]e^{2x}=7.3333[/tex]
Take natural logs of each side.
[tex]2x=ln(7.3333)=1.9924[/tex]
Divide each side by 2.
x = 0.9962

Answer: x = 0.996 (nearest thousanth)

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