Upon balancing the equation below, how many moles of calcium chloride are needed to react completely with 4.3 moles of silver nitrate? AgNO3 + CaCl2 yields AgCl + Ca(NO3)2

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22-12-2017
Chemistry

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Upon balancing the equation below, how many moles of calcium chloride are needed to react completely with 4.3 moles of silver nitrate? AgNO3 + CaCl2 yields AgCl + Ca(NO3)2

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Dejanras Dejanras · Answer 1 · 2017-12-28T11:53:07+01:00

Dejanras Dejanras

28-12-2017

2AgNO₃(silver-nitrate)+ CaCl₂(calcium-chloride) = 2AgCl(silver-chloride) + Ca(NO₃)₂(calcium-nitrate)
n(AgNO₃) = 4,3mol
n(CaCl₂) = ?
From reaction: n(AgNO₃) : n(CaCl₂) = 2 :1
4,3mol : n(CaCl₂) = 2 :1, amount of calcium-chloride is two times less than amount of silver-nitrate.
n(CaCl₂) = 2,15 mol

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