A student has a sample of isopropanol (C3H7OH) that has a mass of 78.6 g. The molar mass of isopropanol is 60.1 g/mol. How many moles of isopropanol are contained in this sample? 0.765 1.31 78.6 4,720

Respuesta :

78.6 g ( 1mol / 60.1g) = 1.31 mol isopropanol
so 1.31 would be your answer! I hope this helps!! ^^

Answer

  • moles of isopropanol are 1.31 moles.

Data given

  • mass of isopropanol = 78.6 g
  • molar mass of isopropanol = 60.1 g/mol

Solution

  • mole = given mass ÷ molar mass
  •  mole  = 78.6÷60.1 = 1.31 moles

Result

  • The calculated moles of isopropanol are 1.31 moles.