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The amount of cholesterol in a person's body produced by their liver and other cells is proposed to be normally distributed with mean 75% and standard deviation 0.5%. the probability that a person produces more than 76.7% of the cholesterol in their body is

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Yna9141
Calculate for the z-score of the given value through the equation,

   z-score = (x - m) / s

Where x is the data, m is the mean, and s is the standard deviation. Substituting the known values,

   z-score = (76.7 - 75) / 0.5

   z-score = 3.4

Converting this to percentage will give us 99.87%. The percentage not covered in this is 0.13%.

ANSWER: 0.13%

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