Write a program that lets a user enter n and that outputs n! (meaning n*(n-1)*(n-2)*...*2*1). hint: initialize a variable totalvalue to n, and use a loop variable i that counts from n-1 down to 1.
// This code snippet calculates n! and stores the answer in the variable p. // Handle 0! = 1 separately. if (n==0) { p = 1; } else { // Initialize p = n p = n;
// While loop while (n>1) { p = p*(n-1); n = n-1; } }
