a speeding car traveling north at 80mph passes the tramway intersection when the police begin pursuit. The police start 6 miles south of tramway traveling at 100mph. How many miles north of tramway will they be when they catch up with the speeding car?

Respuesta :

Refer to the diagram shown below.

Define
x =  distance, miles, that the speeding car travels before the police catch up.
t = time, hrs, before the police catch up.
Then
(80 m/h)*(t h) = (x mi)
80t = x                 (1)

(100 mi/h)*(t h) = (x+6 mi)
100t = x + 6          (2)

Subtract (1) from (2).
100t - 80t = x+6 - x
20t = 6
t = 6/20 = 0.3 h

From (1), obtain
x = 80*0.3 = 24 mi.

Answer:  24 miles
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