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acetylene (C2H2) burns in pure oxygen with a very hot flame. The products of this reaction are carbon dioxide and water. How much oxygen is required to react with 52.0 g of acetylene?

Respuesta :

2C2H2 + 5O2 -> 4CO2 + 2H2O, this is a balanced equation representation

C2H2 has mole of mass of 26 g/mol, so for 52g acetylene, it's 2 moles

Therefore, 2 moles C2H2 requires 5 moles of O2

Answer:

160.0 g

Explanation:

Since O2 has an amu of  32 and it has a coefficent of five in the balanced equation you would do 32 x 5 = 160.0g