A bag contains 3 red marbles, 2 blue marbles, and 5 green marbles. What is the probability of selecting a red marble, replacing it in the bag and then selecting a green marble?

[tex]A) \frac{7}{10}
B) \frac{4}{5}
C) \frac{3}{20}
D) \frac{1}{10} [/tex]

Respuesta :

the answer is a.........
 Sample space {3 R, 2 B, 5 G} = 10 Total outcome

P(1 RED MARBLE) = 3/10
P(1 GREEN MARBLE) = 5/10

P( 1 RED AND ONE GREEN) = 3/10 x 5/10 = 15/100 = 3/20