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Solve x2 + 9x + 9 = 0.

quantity of negative 9 plus or minus 3 square root of 5 all over 2
quantity of 9 plus or minus 3 square root of 5 all over 2
quantity of negative 9 plus or minus square root of 117 all over 2
quantity of 9 plus or minus square root of 117 all over 2

Respuesta :

Banabanana
[tex]x^2 + 9x + 9 = 0\\ \\ D=b^2-4ac=9^2-4*1*9=81-36= 45 \\ \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ \\ x_{1,2}= \frac{-9б \sqrt{45} }{2}= \frac{-9б3 \sqrt{5} }{2} [/tex]
texaschic101
x = (-b (+-)sqrt (b^2 - 4ac) / 2a

x^2 + 9x + 9 = 0
a = 1
b = 9
c = 9

x = -9 (+-) sqrt (9^2 - 4(1)(9)) / 2(1)
x = -9 (+-) sqrt (81 - 36) / 2
x = -9 (+-) sqrt (45) / 2
x = -9 (+-) sqrt (9 * 5) / 2
x = -9 (+-) (3 sqrt 5) / 2 <===