contestada

How do you do,

2^n=88

rounding your answers to the nearest ten-thousandth (using logs)

I forget how to do the equation

Respuesta :

bcalle
2^n = 88
To solve an equation with a variable in the power you have to use logs.
Take the log of both sides.
log 2^n = log 88
Using the power rule of logs, bring the n to the front, it becomes a coefficient.
n* log 2 = log 88
Divide both sides by log 2
n = (log 88)/(log 2)
n = 6.4594