Respuesta :
[tex](k\circ h)(x)=k(h(x))[/tex]
[tex]\displaystyle k(h(x))= \frac{1}{h(x)}= \frac{1}{5x} [/tex]
[tex]\displaystyle k(h(x))= \frac{1}{h(x)}= \frac{1}{5x} [/tex]
For those who may still need it in the future, the correct answer is actually: B