We have a slope, and we have a point.
Thus, we can use the point-slope form of a line, in the form:
[tex]y - y_1 = m(x - x_1)[/tex], where (x₁, y₁) are the points of interest and m is the slope.
Substituting the points and the slope in, we produce:
[tex]y - 5 = -\frac{2}{3}(x + 6)[/tex]
[tex]3y - 15 = -2x - 12[/tex]
[tex]3y = -2x + 3[/tex]
Thus, [tex]y = -\frac{2}{3}x + 1[/tex] is our line.
