The general equation of the circle with centre (h,k) and radius r is,
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Simplify the given equation to obtain the equation in general equation.
[tex]\begin{gathered} (x-7)^2+(y-2)^2=10 \\ (x-7)^2+(y-2)^2=(\sqrt[]{10})^2 \end{gathered}[/tex]
On compare the equation with general equation the centre and radius is,
[tex](h,k)=(7,2)[/tex]
And
[tex]r=\sqrt[]{10}[/tex]
So centre is (7,2) and radius is
[tex]\sqrt[]{10}[/tex]
Option B is correct answer.
