From the original equation we have:
[tex]-5x+7y=3[/tex][tex]7y=5x+3[/tex][tex]y=\frac{5}{7}x+\frac{3}{7}[/tex]The slope of this line is 5/7 and for the new equation to be parallel to the original must have the same slope, and using the point-slope formula we have:
[tex]y-(-4)=\frac{5}{7}(x-9)[/tex][tex]y+4=\frac{5}{7}x-\frac{45}{7}[/tex][tex]y=\frac{5}{7}x-\frac{45}{7}-4[/tex][tex]y=\frac{5}{7}x-\frac{73}{7}[/tex]