AubinB93497 AubinB93497

25-10-2022
Mathematics

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Find mZABD and mZCBD given mZABC =111°A(-10x + 58)(6x + 41)BmZABD =and mZCBD =

Find mZABD and mZCBD given mZABC 111A10x 586x 41BmZABD and mZCBD class=

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DonovenQ219742 DonovenQ219742

25-10-2022

Given;

[tex]\begin{gathered} m\angle ABD=(-10x+58)^0 \\ m\angle CBD=(6x+41)^0 \\ m\angle ABC=111^0 \end{gathered}[/tex]

From the given diagram;

[tex]m\angle ABD+m\angle CBD=m\angle ABC[/tex]

substituting the given;

[tex]undefined[/tex]

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