Solution
We want the equation of the line that is parallel to the given line and passes through the given point;
[tex](-6,2)\text{ }y=-\frac{2}{3}x-3[/tex]
For the equation, the slope can be seen to be;
[tex]m=-\frac{2}{3}[/tex]
The line we want to get will have this same slope and pass through the given point, so in point slope form, we have;
[tex]\begin{gathered} y-2=-\frac{2}{3}(x+6) \\ y-2=-\frac{2}{3}x-4 \\ y=-\frac{2}{3}x-2 \end{gathered}[/tex]
Thus, the answer is;
[tex]y=-\frac{2}{3}x-2[/tex]
