.The inequality is given by:
[tex]2.75+1.25t<8[/tex]Subtract 2.75 from both sides of the inequality:
[tex]\begin{gathered} 2.75-2.75+1.25t\lt8-2.75 \\ 1.25t\lt5.25 \\ \text{ Divide both sides by }1.25 \\ \frac{1.25t}{1.25}\lt\frac{5.25}{1.25} \\ t\lt4.2 \end{gathered}[/tex]Therefore, the maximum time of additional hour is 4