Respuesta :
Explanation
We can solve the question using the formula below
[tex]\begin{gathered} P\left(H∪V\right)=P\left(H\right)+P\left(V\right)−P\left(H∩V\right) \\ Therefore; \\ P\left(H\cup V\right)^{\prime}=1-P\left(H∪V\right) \end{gathered}[/tex]Therefore;
The probabilty of those that eat one or more of both foods
[tex]\begin{gathered} P\left(H∪V\right)=P\left(H\right)+P\lparen V)−P\left(H∩V\right) \\ P\left(H∪V\right)=0.71+0.65-0.48 \\ P\left(H∪V\right)=0.88 \end{gathered}[/tex]Hence, we can find the probability of those that do not like both ham and vegetable
[tex]\begin{gathered} P(H\cup V)^{\prime}=1-P(H\cup V) \\ =1-0.88=0.12 \end{gathered}[/tex]Answer: 0.12
