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Logarithm 2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H^+,measured in moles/liter) of the fluid using the model shown below:pH = -log(H^+)A lab technician finds that a sample of fluid has a pH of 4.5. What is the hydrogen ion concentration of the fluid?

Logarithm 2 The alkalinity of a fluid pH can be modeled in terms of its hydrogen ion concentration Hmeasured in molesliter of the fluid using the model shown be class=

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ok. We are given the following equation:

[tex]ph=-\log (H)[/tex]

Where:

[tex]\begin{gathered} P=\text{ alkalinity} \\ H=\text{ hydrogen ion concentration} \end{gathered}[/tex]

Since we are asked to determine "H" we will solve for "H" in the equation. To do that we will first multiply both sides by -1:

[tex]-ph=\log (H)[/tex]

Now, we will use the following property of logarithms:

[tex]\log _aB=c\rightarrow B=a^c[/tex]

Applying the property and having into account that:

[tex]\log (H)=\log _{10}(H)[/tex]

We get:

[tex]10^{-pH}=H[/tex]

Now we substitute the given value of "pH = 4.5":

[tex]10^{-4.5}=H[/tex]

Solving the operation:

[tex]0.000032=H[/tex]

Therefore, the hydrogen ion concentration of the fluid is 0.000032

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