[tex]\begin{gathered} A)-18-3=-15\Rightarrow false(mistake) \\ B)x=-126 \end{gathered}[/tex]
Explanation
[tex]\begin{gathered} \frac{x}{6}+3=-18 \\ \end{gathered}[/tex]
Step 1
to find the solution we need to isolate x, so
a)subtract 3 in both sides
so
[tex]\begin{gathered} \frac{x}{6}+3=-18 \\ subtract\text{ 3 in both sides} \\ \frac{x}{6}+3-3=-18-3 \\ \frac{x}{6}=-21 \end{gathered}[/tex]
therefore, the mistake the student did is
he did :
[tex]-18-3=-21\Rightarrow False[/tex]
Step 2
now, to find the true value for x , let's continue with the solution
[tex]\begin{gathered} \frac{x}{6}=-21 \\ \text{Multiply both sides by 6} \\ \frac{x}{6}\cdot6=-21\cdot6 \\ x=-126 \end{gathered}[/tex]
therefore, the answer is
[tex]x=-126[/tex]
I hope this helps you
