a passenger in an airplane at an altitude of 53 km sees two towns directly to the east of the plane the angles of depression to the towns of 28° and 55°. How far apart are the towns? round Answer to two decimal places.

a passenger in an airplane at an altitude of 53 km sees two towns directly to the east of the plane the angles of depression to the towns of 28 and 55 How far a class=

Respuesta :

Answer:

The two towns are 62.57km apart.

Explanation:

A diagram representing the problem is redrawn and attached below:

From trigonometric ratios:

[tex]\begin{gathered} \tan 55\degree=\frac{53}{OA} \\ OA\times\tan 55\degree=53 \\ OA=\frac{53}{\tan 55\degree} \\ OA=37.11\operatorname{km} \end{gathered}[/tex]

Similarly:

[tex]\begin{gathered} \tan 28\degree=\frac{53}{OB} \\ OB\times\tan 28\degree=53 \\ OB=\frac{53}{\tan 28\degree} \\ OB=99.68\operatorname{km} \end{gathered}[/tex]

Therefore, the distance between the two towns is:

[tex]\begin{gathered} AB=OB-OA \\ =99.68-37.11 \\ =62.57\operatorname{km} \end{gathered}[/tex]

The two towns are 62.57km apart.

Ver imagen HoldanC305112