To solve the exercise you can use the slope formula:
[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \text{ Where m is the slope and} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are two points through which the line passes} \end{gathered}[/tex]So, in this case, you have
[tex]\begin{gathered} (x_1,y_1)=(7,-12) \\ (x_2,y_2)=(-9,36) \end{gathered}[/tex][tex]\begin{gathered} m=\frac{36-(-12)}{-9-7} \\ m=\frac{36+12}{-16} \\ m=\frac{48}{-16} \\ m=-3 \end{gathered}[/tex]Therefore, the slope of the line that passes through the given points is -3.
