Answer:
21
Explanation:
Given the below sequence;
[tex]5,9,13,17[/tex]Looking at the sequence, we can see that the first term is 5 and the common difference is 4 as shown below;
[tex]9-5=13-9=17-13=4[/tex]So the sequence is an arithmetic progression with a = 5 and d = 4.
Let's go ahead and determine the 5th term of the sequence;
[tex]\begin{gathered} a_5=a+(n-1)d \\ =5+(5-1)4 \\ =5+16 \\ =21 \end{gathered}[/tex]