Solution:
Given the quadratic equation below
[tex]x²+8x=10[/tex]Solving the quadratic equation by completing the square method;
[tex]\begin{gathered} Where \\ b=8 \\ Add\text{ }(\frac{b}{2})^2\text{ to both sides of the equation} \\ (\frac{8}{2})^2=4^2=16 \\ x^2+8x+4^2=10+16 \\ (x+4)^2=26 \end{gathered}[/tex]Then find the square root of both sides
[tex]\begin{gathered} \sqrt{(x+4)^2}=\pm\sqrt{26} \\ x+4=\pm\sqrt{26} \\ Subtract\text{ 4 from both sides} \\ x+4-4=-4\pm\sqrt{26} \\ x=-4\pm\sqrt{26} \end{gathered}[/tex]Thus;
[tex]x=-4\pm\sqrt{26}[/tex]Hence, the answer is B
