[tex]y=-3x-12[/tex]
1) Note that we need to find a perpendicular line. Perpendicular lines have reciprocal and opposite slopes. So we know that the slope we need is -3
2) We also know that it must pass through (-2,-6), so let's plug the slope -3 the point (-2,-6) so that we can find the linear coefficient:
[tex]\begin{gathered} y=mx+b \\ -6=-3(-2)+b \\ -6=6+b \\ -6-6=b \\ b=-12 \end{gathered}[/tex]
