Given:
The power take by the dryer is
[tex]\begin{gathered} P=4\text{ kW} \\ P=4000\text{ W} \end{gathered}[/tex]
The dryer is connected to source of
[tex]V=220\text{ V}[/tex]Required: the current use by the dryer
Explanation:
we know that power taken by any appliance is given by
[tex]P=VI[/tex]here, V is the voltage of the source and I is the current drawn by the electric appliance.
Plugging all the values in the above formula, we get
[tex]\begin{gathered} 4000\text{ W}=220\text{ V}I \\ I=\frac{4000\text{ W}}{220\text{ V}} \\ I=18.18\text{ A} \end{gathered}[/tex]Thus, the current used by the dryer is
[tex]18.18\text{ A}[/tex]