Respuesta :

[tex]\begin{gathered} \text{slope, m of the line = }\frac{change\text{ in y}}{change\text{ in x}} \\ \\ m\text{ = }\frac{1-0}{0-(-4)} \\ m=\frac{1}{0+4} \\ m=\frac{1}{4} \end{gathered}[/tex][tex]\begin{gathered} \text{one point the line is passing through is ( -4, 0)} \\ \text{ using slope and one point form, that is y-y}_1=m(x-x_{1)} \\ we\text{ have} \\ y-0=\text{ }\frac{1}{4}(x-(-4)\text{ )} \\ y\text{ = }\frac{1}{4}(x+4) \\ y\text{ = }\frac{1}{4}x\text{ + }\frac{1}{4}(4) \\ \\ y=\text{ }\frac{1}{4}x\text{ + 1} \end{gathered}[/tex]