Answer:
The equation of the line is;
[tex]y=-\frac{3}{4}x+5[/tex]
Explanation:
Given that the line has a slope of;
[tex]m=-\frac{3}{4}[/tex]
And passes through the point;
[tex](8,-1)[/tex]
Applying the point-slope equation of straight line;
[tex]y-y_1=m(x-x_1)[/tex]
substituting the given values and solving;
[tex]\begin{gathered} y-(-1)=-\frac{3}{4}(x-8) \\ y+1=-\frac{3}{4}x-\frac{3}{4}(-8) \\ y+1=-\frac{3}{4}x+6 \\ y=-\frac{3}{4}x+6-1 \\ y=-\frac{3}{4}x+5 \end{gathered}[/tex]
Therefore, the equation of the line is;
[tex]y=-\frac{3}{4}x+5[/tex]
