From the problem, we have an inequality of :
[tex]5x+9\le24[/tex]Subtract 9 to both sides of the inequality :
[tex]\begin{gathered} 5x+9-9\le24-9 \\ 5x\le15 \end{gathered}[/tex]Divide both sides by 5 :
[tex]\begin{gathered} \frac{5x}{5}\le\frac{15}{5} \\ x\le3 \end{gathered}[/tex]The answer is x ≤ 3
