[tex]B)\:y=(x-1)(x-3)[/tex]
1) The best way to tackle questions like this is to locate the x-intercepts. Since according to the options the leading coefficient is 1, we just need to locate the zeroes and plug them into the quadratic equation form, in its factored form.
2) So now, let's write out the factored form and plug the zeroes into them:
[tex]\begin{gathered} y=a(x-x_1)(x-x_2) \\ y=1(x-1)(x-3) \\ y=(x-1)(x-3) \end{gathered}[/tex]
