Answer:
30.95 cm
Explanation:
The focal length f, the object distance do, and the image distance di are related with the following equation:
[tex]\frac{1}{f}=\frac{1}{d_0}+\frac{1}{d_i}[/tex]So, replacing the values, we get:
[tex]\frac{1}{6.25}=\frac{1}{5.20}+\frac{1}{d_i}[/tex]Then, solving for di, we get:
[tex]\begin{gathered} \frac{1}{6.25}-\frac{1}{5.2}=\frac{1}{d_i} \\ -\frac{21}{650}=\frac{1}{d_i}_{} \\ -\frac{650}{21}=d_i \\ -30.95\operatorname{cm}=d_i \end{gathered}[/tex]Therefore, the image distance is 30.95 cm
