We will apply the principle of similar triangles to solve this question
Given that
[tex]\begin{gathered} AB=5 \\ BC=13 \end{gathered}[/tex]
Method: Find side AC
We will use the Pythagoras theorem to evaluate AC
[tex]\text{hypotenuse}^2=\text{opposite}^2+\text{adjacent}^2[/tex]
[tex]13^2=5^2+AC^2[/tex][tex]\begin{gathered} AC^2=13^2-5^2 \\ AC^2=169-25 \\ AC^2=144 \\ AC=\sqrt[]{144} \\ AC=12 \\ \end{gathered}[/tex]
T
