Respuesta :

[tex]\begin{gathered} \sin \theta=\frac{y}{r} \\ \sec \theta=\frac{r}{x} \end{gathered}[/tex]

Given the conditions in the question:

1. sin θ > 0, therefore, it must be positive. From that, we can conclude that y must be on the positive side, therefore, located at the top of the coordinate plane.

2. sec θ < 0, therefore, it must be negative. From that, we can conclude that x must be on the negative side, therefore, located at the left side of the coordinate plane.

Therefore, the quadrant that the θ belongs to is in the top and left of the coordinate plane and that is Quadrant II.