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An auto mechanic recommends that 3 ounces of isopropyl alcohol be mixed with a tankful of gas (14 gallons ) to increase the octane of the gasoline for better engine performance. At this rate, how many gallons of gas can be treated with a 16-ounce bottle of alcohol (You don’t need to translate or understand just solve the word problem please )

An auto mechanic recommends that 3 ounces of isopropyl alcohol be mixed with a tankful of gas 14 gallons to increase the octane of the gasoline for better engin class=

Respuesta :

Let be "x" the number of gallons of gas that can be treated with a 16-ounce bottle of alcohol.

According to the information given in the exercise, 3 ounces of isopropyl alcohol should be mixed with 14 gallons of gas.

Then, you can set up the following proportion:

[tex]\frac{14}{3}=\frac{x}{16}[/tex]

Now you have to solve for "x":

[tex]\begin{gathered} (16)(\frac{14}{3})=x \\ \\ \frac{224}{3}=x \\ \\ x\approx74.67 \end{gathered}[/tex]

Therefore, the answer is:

[tex]\approx74.67\text{ }gallons[/tex]

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