Given,
The initial height of H feet.
The initial velocity of the object is Vo.
The equation of the path of projectile is,
[tex]y=h+x\text{ tan }\theta-\frac{x^2}{2V_0\cos ^2\theta}_{}\text{ }[/tex]This is the expression of the projectle path.
Hence, the path of the projectile object is y = h + xtan(theta) - x²/2V₀²cos²(theta)
