Given:
The perimeter of the rectangular field is 1100 feet.
According to the question,
l=9w
To find the dimensions:
Substitute l=9w in the perimeter formula,
[tex]\begin{gathered} 2(l+w)=1100 \\ 2(9w+w)=1100 \\ 20w=1100 \\ w=55\text{ f}eet \end{gathered}[/tex]Since the width of the rectangle is 55 feet.
The length of a rectangle is,
[tex]55\times9=495\text{ f}eet[/tex]Hence,
The width of the rectangle is 55 feet.
The length of a rectangle is 495 feet.
