The volume V of a cone with radius r and height h is:
[tex]V=\frac{1}{3}\pi r^{2}h[/tex]
And the radius is half the diameter. Since this cone has a diameter of 12 m, the radius is:
[tex]r=\frac{12m}{2}=6m[/tex]
And the height is 8m. Thus, the volume V is:
[tex]\begin{gathered} V=\frac{1}{3}\pi(6m)^28m \\ \\ V=\frac{\pi}{3}(36m^2)8m \\ \\ V=\frac{\pi}{3}(288)(m^2\cdot m) \\ \\ V=\pi\cdot\frac{288}{3}m^3 \\ \\ V=96\pi m^{3} \end{gathered}[/tex]
Now, using 3.14 for π, we obtain:
[tex]\begin{gathered} V=96\cdot3.14m^3 \\ \\ V=301.44m^{3} \end{gathered}[/tex]
Therefore, the volume of that cone is 301.44m³.
