Given.
The distance covered by the snail in 4 minutes is 10 cm.
The speed of snail is,
[tex]\begin{gathered} Spe\text{ed=}\frac{dis\tan ce}{time} \\ =\frac{10}{4}\frac{cm}{\min } \\ =2.5\text{ cm/min} \end{gathered}[/tex]The distance covered by snail in 6 minute is,
[tex]\begin{gathered} \text{Distance}=\text{speed }\times time \\ =2.5\times6 \\ =15\text{ cm} \end{gathered}[/tex]Hence, the distance covered by the snail is 15 cm.