Respuesta :
Critical angle for the total internal reflection icrit, Ī² = Ā 78.28ā°
Critical angle for the total internal reflection crit, Ī± = 17,22ā°
We have the refractive index of core, [tex]n_c_o_r_e[/tex] = 1.46
We have the refractive index of clad , [tex]n_c_l_a_d[/tex] = 1.4
Critical angle can be defined as the incidence angle which results in the refraction angle being equal to Ā at that angle of incidence.
For Total Internal Reflection to occur, the incidence angle must be greater than the critical angle.
We know that the critical angle, Īø is given by:
sinĪø = [tex]\frac{n_c_l_a_d}{n_c_o_r_e}[/tex]
sinĪø = [tex]\frac{1.4}{1.46}[/tex]
sinĪø = 0.959 = sinā»Ā¹(0.979) = 78.28ā°
Ī² = Īø = 78.28ā°
Now, for Ī±:
[tex]\frac{sin(90-\alpha )}{sin\alpha } = \frac{1}{n_c_o_r_e}[/tex]
sinĪ± = sin(90ā°-78.28ā°) Ć 1.46
sinĪ± = sin(11.72ā°) Ć 1.46
Ī± = sinā»Ā¹(0.296)
Ī± = 17,22ā°
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Critical angle for total internal reflection icrit Ī² = 78.28ā°
Critical angle for total internal reflection crit, Ī± = 17.22ā°
- The critical angle can be defined as the Ā angle of incidence at which the angles of refraction are equal to angle of incidence.
- The angle of incidence must be greater than the critical angle for total internal reflection to occur.
The refractive index of the core is ncore = 1.46.
The refractive index of clad is nclad = 1.4.
We know that the critical angle, Īø is given by:
sinĪø = nclad/ ncore
sinĪø = 1.4/1.46
sinĪø = 0.959
sinā»Ā¹(0.979) = 78.28ā°
Ī² = Īø = 78.28ā°
Now, for Ī±:
sin(90- Ī±) / sin Ī± = 1 / ncore
sinĪ± = sin(90ā°-78.28ā°) Ć 1.46
sinĪ± = sin(11.72ā°) Ć 1.46
Ī± = sinā»Ā¹(0.296)
Ī± = 17.22ā°
Critical angle for icrit Ī² = 78.28ā°
Critical angle for crit Ī± = 17.22ā°
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