Respuesta :

[tex]\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=5 \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (5)^3}{3}\implies V=\cfrac{500\pi }{3} \\\\\\ V\approx 524~m^3 \end{array}[/tex]

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