[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]
0.12
Explanation:
[tex] \mathfrak {molarity = \frac{no. \: of \: moles}{volume \: of \: solution} }[/tex]
[tex] \sf 1 \: mole \: of \: Al_2(SO_4)_3 = 342g \\ \\ \sf 31.1g \: of \: Al_2(SO_4)_3 = \frac{31.1}{342} = 0.09 \: moles \\ \\ \sf volume = 755ml = 0.755l[/tex]
[tex] \sf \longmapsto molarity = \frac{0.09}{0.755} \\ \\ \\ \sf \longmapsto 0.12 \: mol \: {l}^{ - 1} [/tex]
